Odpowiedź :
(x-2)(x+2)-(x-2)²=-y
x²+2x-2x-4-(x²-4x+4)=-y
- y=x²+2x-2x-4-x²+4x-4
-y=4x-8
y=-4x+8
x²+2x-2x-4-(x²-4x+4)=-y
- y=x²+2x-2x-4-x²+4x-4
-y=4x-8
y=-4x+8
(x-2)(x+2)-(x-2)kwadrat=-y
(xkwadrat+2x-2x-4)-(xkwadrat+4)=-y
(xkwadrat-4)-(xkwadrat+4)=-y
-y=0
y=0
(xkwadrat+2x-2x-4)-(xkwadrat+4)=-y
(xkwadrat-4)-(xkwadrat+4)=-y
-y=0
y=0