Odpowiedź :
x(2-x)-3x = x{x-(5+2x)}
2x - x² - 3x = x²- (5+2x)
-x - x² = x² - 5 - 2x
-x = - 5 - 2x | +2x
x = 5
Chyba tak. :)
2x - x² - 3x = x²- (5+2x)
-x - x² = x² - 5 - 2x
-x = - 5 - 2x | +2x
x = 5
Chyba tak. :)
x(2-x)-3x = x[x-(5+2x)]
2x -x² - 3x = x(x-5-2x)
-x² - x = x(-x - 5)
-x² - x = -x² -5x
-x² - x +x² + 5x = 0
4x = 0
x = 0
2x -x² - 3x = x(x-5-2x)
-x² - x = x(-x - 5)
-x² - x = -x² -5x
-x² - x +x² + 5x = 0
4x = 0
x = 0