[tex]3x^3=24\\ x^3=8\\ x=\sqrt[3]{8}=2[/tex]
równanie ma 1 rozwiązanie
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[tex] sin\alpha=\frac{2}{3}\\ \\ \\ sin^2\alpha + cos^2\alpha=1\\ (\frac{2}{3})^2+cos^2\alpha = 1\\ \frac{4}{9}+cos^2\alpha=1\\ cos^2\alpha=\frac{5}{9}\\ cos\alpha=\sqrt{\frac{5}{9}}=\frac{\sqrt{5}}{3}\\ \\ \\ ctg\alpha=\frac{cos\alpha}{sin\alpha}=\frac{\frac{\sqrt{5}}{3}}{\frac{2}{3}}=\frac{\sqrt{5}}{3}\cdot \frac{3}{2}=\frac{\sqrt{5}}{2}\\ [/tex]
