Odpowiedź :
1.(√2+√3)(√6+√3) = √12+√6+√18+√9 = 2√3+√6+3√2+3
2.(x√2+1)(x-2√2) = x²√2-4x+x-2√2 = x²√2-2√2-3x
3.(x+√2)(2√2+x) = 2x√2+x²+4+x√2 = x²+3x√2+4
2.(x√2+1)(x-2√2) = x²√2-4x+x-2√2 = x²√2-2√2-3x
3.(x+√2)(2√2+x) = 2x√2+x²+4+x√2 = x²+3x√2+4
zad1 (√2+√3)(√6+√3) = √12+√6+√18+√9 = 2√3+√6+3√2+3
zad2 (x√2+1)(x-2√2) = x²√2-4x+x-2√2 = x²√2-2√2-3x
zad3 (x+√2)(2√2+x) = 2x√2+x²+4+x√2 = x²+3x√2+4
chyba tak to powinno byc
zad2 (x√2+1)(x-2√2) = x²√2-4x+x-2√2 = x²√2-2√2-3x
zad3 (x+√2)(2√2+x) = 2x√2+x²+4+x√2 = x²+3x√2+4
chyba tak to powinno byc