Odpowiedź :
wzór siarczanu (VI) żelaza (III) - Fe2(SO4)3
M Fe =56 g/mol
M S = 32g/mol
M O= 16g/mol
2*56g/mol + 3*32g/mol + 12*16g/mol =400g/mol
M Fe =56 g/mol
M S = 32g/mol
M O= 16g/mol
2*56g/mol + 3*32g/mol + 12*16g/mol =400g/mol