Bart90pl
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rozwiaż: x³ -2x²-x+2=0
x⁴-5x³+x²+11x+4=0
(x-2)(-x²-x-2)<0



Odpowiedź :

x³ - 2x² - x + 2 = 0
x²(x - 2) - (x - 2) = 0
(x² - 1)(x - 2) = 0
(x - 1)(x + 1)(x - 2) = 0
x₁ = 1
x₂ = 2
x₃ = -1

x⁴ - 5x³ + x² + 11x + 4 = 0
(x³ - 6x² + 7x + 4)(x + 1) = 0
(x² - 2x - 1)(x - 4)(x + 1) = 0
x₁ = 1 - √2
x₂ = 1 + √2
x₃ = -1
x₄ = 4

(x-2)(-x²-x-2)<0
x₁ = 2
x ∈ (2; ∞)
Janek191
x³ -2x² - x +2 = 0
x(x² -1) -2(x² -1) = 0
(x - 2)(x² -1) = 0
(x -2 )(x -1)(x +1) = 0
x =2 lub x =1 lub x = -1
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Zobacz obrazek Janek191
x3-2x2-x+2=0
x(x2-1)-2(x2-1)=0
(x-2)(x2-1)=0
(x-2)(x-1)(x+1)=0
x=2 lub x=1 lub x=-1
nie wiem czy dobrze

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