Odpowiedź :
( 2b - 5 ) ( 3-2b) - ( 3b+2 ) ( b-6 ) = 6b - 4b² - 15 + 10b -(3b²-18b+2b-12) = 6b - 4b² - 15 + 10b - 3b² + 18b - 2b + 12 = -7b² +32b -3
(2b-5)(3-2b)-(3b+2)(b-6)=2b(3-2b)-5(3-2b)-3b(b-6)+2(b-6)= 6b -4b -15 +10b - 3b²+18b= 30b -15 +3b²