Hej!
[tex]\frac{2}{x+2}-\frac{4x}{x^2-4}=0\\\\x+2\neq0\rightarrow x\neq-2\\\\x^2-4\neq0\rightarrow(x+2)(x-2)\neq0\rightarrow x\neq-2 \ oraz \ x\neq2\\\\\mathbb{D}:\mathbb{R}-\{-2;2\}\\\\\frac{2}{x+2}=\frac{4x}{x^2-4}\\\\2(x^2-4)=4x(x+2)\\\\2x^2-8=4x^2+8x\\\\4x^2+8x-2x^2+8=0\\\\2x^2+8x+8=0 \ \ |:2\\\\x^2+4x+4=0\\\\(x+2)^2=0\\\\x+2=0\rightarrow x=-2\not\in\mathbb{D}[/tex]
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