Zad. 1
a) F = m × g
m = 84 kg g = 10 m/s²
F = 84 × 10 = 840N
[F] = kg × m/s² = N
b) ... 14 kg.
F = m × g | :g
m = F/g F = 140N
m = 140 ÷ 10 = 14kg
[m] = N ÷ m/s² = kg × m/s² ÷m/s² = kg
Zad. 2
a) Fsilnika = 200kN = 200000N
Fc = 12t = 12000kg = 120000N
Fw = 200000N - 120000N = 80000N
b) wektor siły jest zwrócony do góry.