Odpowiedź :
a) (x+2)(y+1)= xy+x+2y+2
b)(2a+1)(a²+b)= 2a³+2ab+a²+b
c) (x-y)(z+1)= xz+x-yz-y
b)(2a+1)(a²+b)= 2a³+2ab+a²+b
c) (x-y)(z+1)= xz+x-yz-y
a) (x+2)(y+1)= xy + x +2y+2
b)(2a+1)(a²+b)=2a(sześcian) +2ab+a²+b
c) (x-y)(z+1)=xz+x-yz-y
b)(2a+1)(a²+b)=2a(sześcian) +2ab+a²+b
c) (x-y)(z+1)=xz+x-yz-y
a)xy+x+2y+2
b)2a*a*a+2ab+a*a*+b=2a(do 5 potegi)+2ab+b
c)xz+x-yz+y
b)2a*a*a+2ab+a*a*+b=2a(do 5 potegi)+2ab+b
c)xz+x-yz+y