a)
[tex]0,2^{12}\cdot5^{12}\cdot(-1)^{12}=\\=[0,2\cdot5\cdot(-1)]^{12}=\\=[1\cdot(-1)]^{12}=\\=(-1)^{12}=1[/tex]
b)
[tex](1\frac{1}{2})^{3}\ :\ (2\frac{1}{4})^{3}\cdot3^{3}=\\=(1\frac{1}{2}\ :\ 2\frac{1}{4}\cdot3)^{3}=\\=(\frac{3}{2}\ :\ \frac{4}{9}\cdot\frac{3}{1})^{3}=\\=(\frac{3}{2}\cdot\frac{4}{9}\cdot\frac{3}{1})^{3}=\\=(\frac{2}{3}\cdot\frac{3}{1})^{3}=2^{3}=8[/tex]