Odpowiedź :
propanol - C₃H₇OH
mC₃H₇OH= mC₃+mH₇+mOH
mC3H7OH=3*12u+7*1u+16u+1u=36u+7u+17u=60u
dekanol - C10H21OH
mC10H21OH= 10 * 12u+21*1u+16u=120u+21u+17u=158u
mC₃H₇OH= mC₃+mH₇+mOH
mC3H7OH=3*12u+7*1u+16u+1u=36u+7u+17u=60u
dekanol - C10H21OH
mC10H21OH= 10 * 12u+21*1u+16u=120u+21u+17u=158u