Odpowiedź:
Szczegółowe wyjaśnienie:
a.
[tex]-4x+3x^2+8-6x-3(x^2+2x+1)=3x^2-10x+8-3x^2-6x-3=-16x+5\\-16*(0,01^{0,5})+5=-16*\frac{1}{100} +5=-0,16+5=4,84\\[/tex]
b.
[tex]2a^3-2a^2-2a+a^2-a-1-2(a^3-a^2+a-1)=2a^3-a^2-3a-1-2a^3+2a^2-2a+2=\\=a^2-5a+1\\(\sqrt{2} -1)^2-5(\sqrt{2} -1)+1=2-2\sqrt{2} +1-5\sqrt{2} +5+1=9-7\sqrt{2} \\[/tex]
c.
[tex]4x^2-12x+9-4x^2-12x-9+4x=-20x\\-20*(16^{0,3}:16^{0,05})=-20*16^{0,3-0,05}=-20*16^{0,25}=-20*16^{\frac{1}{4} }=-20*2=-40[/tex]
d.
[tex][(x-1)(x+1)]^2-x^4-2x^2-1=(x^2-1)^2-x^4-2x^2-1=x^4-2x^2+1-x^4-2x^2-1=\\=-4x^2\\-4(-2\sqrt[4]{9} )^2=-4(-2\sqrt{3} )^2=-4*(4*3)=-48[/tex]
