Odpowiedź:
[tex]a)\\\\(3+x)(3-x)\geq x(5-x)\\\\9-x^2\geq 5x-x^2\\\\-x^2-5x+x^2\geq -9\\\\-5x\geq -9\ \ /:(-5)\\\\x\leq \frac{9}{5}\\\\x\leq 1\frac{4}{5}\\\\x\in(-\infty,1\frac{4}{5}\rangle[/tex]
[tex]b)\\\\(6-2x)^2>(3+2x)^2\\\\36-24x+4x^2>9+12x+4x^2\\\\-24x+4x^2-12x-4x^2>9-36\\\\-36x>-27\ \ /:(-36)\\\\x<\frac{27}{36}\\\\x<\frac{3}{4}\\\\x\in(-\infty,\frac{3}{4})[/tex]
[tex]c)\\\\(x+4)(x-4)\leq (x+1)^2\\\\x^2-16\leq x^2+2x+1\\\\x^2-x^2-2x\leq 1+16\\\\-2x\leq 17\ \ /:(-2)\\\\x\geq -\frac{17}{2}\\\\x\geq -8\frac{1}{2}\\\\x\in\langle-8\frac{1}{2},+\infty)[/tex]
