8.
[tex]a) \ \frac{10-2\sqrt{3}}{2} = \frac{2(5-\sqrt{3})}{2} = 5-\sqrt{3}\\\\b) \ \frac{-3\pi +6}{-3} = \frac{-3(\pi-2)}{-3} = \pi -2\\\\c) \ \frac{\sqrt{6}-\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}\cdot\sqrt{3}-\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}(\sqrt{3}-1)}{\sqrt{2}} = \sqrt{3}-1\\\\d) \ \frac{0,5+1,5\pi}{-0,5} = \frac{0,5+0,5\cdot3\pi}{-0,5}=\frac{0,5(1+3\pi)}{-0,5} =-(1+3\pi) = -1-3\pi[/tex]
