Odpowiedź:
Wyjaśnienie:
Dane; Szukane:
pH =3 [CH3COOH]=?
K = 1,6*10⁻⁵
pH = 3 to [H⁺] = 10⁻³
CH3COOH =[H2O]= CH3COO- + H+
K = [H⁺]*[CH3COO⁻]/[CH3COOH]
[CH3COOH] = [H⁺][CH3COO⁻]/K
[CH3COOH] = (10⁻³)²/(1,6*10⁻⁵)
[ch3COOH] = 10⁻⁶/1,6*10⁻⁵
[CH3COOH] = 0,0625 mol/dm3
