a)
[tex]f(x) = log_3 \ (2x +3)-0,1 \\\\ f(- 1) = log_3 \ (2 \cdot (-1) +3)-0,1 =log_3 \ (-2 +3)-0,1 =log_3 \ (1)-0,1 = \\ = 0-0,1= -0,1[/tex]
b)
[tex]g(x) = log_2 (2x^3+4x+8\sqrt{2}) \\\\ g(\sqrt{2})=log_2 (2 \cdot (\sqrt{2})^3+4 \cdot \sqrt{2}+8\sqrt{2}) =log_2 (4\sqrt{2}+4\sqrt{2}+8\sqrt{2}) = \\ = log_2 (16\sqrt{2})= log_2 (2^4 \cdot 2^{\frac{1}{2}}) =log_2 (2^{4\frac{1}{2}}) =4\frac{1}{2} \cdot log_2 (2) =4\frac{1}{2} \cdot 1=4\frac{1}{2}[/tex]
