Odpowiedź :
[tex]dla \ \x = -1\\\\\frac{5x^{2}-4x+3}{-8x^{5}+5x} = \frac{5\cdot(-1)^{2}-4\cdot(-1)+3}{-8\cdot(-1)^{5}+5\cdot(-1)} = \frac{5\cdot1+4+3}{-8\cdot(-1)-5} = \frac{5+4+3}{8-5} = \frac{12}{3} = 4[/tex]
[tex]dla \ \x = -1\\\\\frac{5x^{2}-4x+3}{-8x^{5}+5x} = \frac{5\cdot(-1)^{2}-4\cdot(-1)+3}{-8\cdot(-1)^{5}+5\cdot(-1)} = \frac{5\cdot1+4+3}{-8\cdot(-1)-5} = \frac{5+4+3}{8-5} = \frac{12}{3} = 4[/tex]