Zad. 9
[tex]\sqrt{32}+3\sqrt{72}-\sqrt{8}= \sqrt{16 \cdot 2}+3\sqrt{36 \cdot 2}-\sqrt{4 \cdot 2}= 4\sqrt{2}+18\sqrt{2}-2\sqrt{2}=20\sqrt{2}[/tex]
[tex]\sqrt{27}-5\sqrt{12}+4\sqrt{48}=\sqrt{9 \cdot 3}-5\sqrt{4 \cdot 3}+4\sqrt{16 \cdot 3}=3\sqrt{3}-10\sqrt{3}+16\sqrt{3}= \\ = 9\sqrt{3}[/tex]
