Odpowiedź :
Jeśli przedział jest otwarty [tex](\frac{24}{32}, \ \frac{25}{32}) = (\frac{48}{64}, \ \frac{50}{64})[/tex], to:
[tex]A. \ \frac{48}{64} \notin (\frac{48}{64}, \ \frac{50}{64}) = (\frac{24}{32}, \ \frac{25}{32}) \\\\ B. \ \ \frac{49}{64} \in (\frac{48}{64}, \ \frac{50}{64}) = (\frac{24}{32}, \ \frac{25}{32}) \\\\ C. \ \frac{50}{64} \notin (\frac{48}{64}, \ \frac{50}{64}) = (\frac{24}{32}, \ \frac{25}{32}) \\\\ D. \ \ \frac{51}{64} \notin (\frac{48}{64}, \ \frac{50}{64}) = (\frac{24}{32}, \ \frac{25}{32})[/tex]
Odp. B
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Jeśli przedział jest zamknięty [tex]\langle \frac{24}{32}, \ \frac{25}{32} \rangle = \langle \frac{48}{64}, \ \frac{50}{64} \rangle[/tex], to:
[tex]A. \ \frac{48}{64} \in \langle \frac{48}{64}, \ \frac{50}{64} \rangle=\langle \frac{24}{32}, \ \frac{25}{32} \rangle \\\\ B. \ \frac{49}{64} \in \langle \frac{48}{64}, \ \frac{50}{64} \rangle=\langle \frac{24}{32}, \ \frac{25}{32} \rangle[/tex]
[tex]C. \ \frac{50}{64} \in \langle \frac{48}{64}, \ \frac{50}{64} \rangle=\langle \frac{24}{32}, \ \frac{25}{32} \rangle \\\\ D. \ \frac{51}{64} \notin \langle \frac{48}{64}, \ \frac{50}{64} \rangle=\langle \frac{24}{32}, \ \frac{25}{32} \rangle[/tex]
Odp. A, B i C.