Hej!
[tex] \frac{3}{2 \sqrt{7} } = \frac{3 \times \sqrt{7} }{2 \sqrt{7} \times \sqrt{7} } = \frac{3 \sqrt{7} }{2 \times 7} = \frac{3 \sqrt{7} }{14} \\ \\ \frac{9}{2 \sqrt{3} } = \frac{9 \times \sqrt{3} }{2 \sqrt{3} \times \sqrt{3} } = \frac{9 \sqrt{3} }{2 \times 3} = \frac{9 \sqrt{3} }{6} = \frac{3 \sqrt{3} }{2} [/tex]
Pozdrawiam! - Julka
Odpowiedź:
e)
[tex] \frac{3}{2 \sqrt{7} } = \frac{3 \times \sqrt{7} }{2 \sqrt{7} \times \sqrt{7} } = \frac{3 \sqrt{7} }{2 \times 7} = \frac{3 \sqrt{7} }{14} [/tex]
f)
[tex] \frac{9}{2 \sqrt{3} } = \frac{9 \times \sqrt{3} }{2 \sqrt{3} \times \sqrt{3} } = \frac{9 \sqrt{3} }{2 \times 3} = \frac{9 \sqrt{3} }{6} = \frac{3 \sqrt{3} }{2} [/tex]
