Zadanie 12
a) [tex]1\frac{1}{4} - \frac{1}{2} - \frac{3}{8} + 1\frac{5}{8} = \frac{5}{4} - \frac{1}{2} - \frac{3}{8} + \frac{13}{8} = \frac{10}{8} - \frac{4}{8} - \frac{3}{8} + \frac{13}{8} = \frac{16}{8} = 2[/tex]
b) [tex](7\frac{3}{5} - 2\frac{7}{10}) - (3\frac{1}{4} + 1\frac{1}{2}) = (\frac{38}{5} - \frac{27}{10}) - (\frac{13}{4} + \frac{3}{2}) = (\frac{76}{10} - \frac{27}{10}) - (\frac{13}{4} + \frac{6}{4})[/tex] =
= [tex]\frac{49}{10} - \frac{19}{4} = \frac{98}{20} - \frac{95}{20} = \frac{3}{20}[/tex]
c) [tex]12 - (2\frac{1}{5} + 3\frac{3}{4}) = 12 - ( \frac{11}{5} + \frac{15}{4}) = 12 - (\frac{44}{20} + \frac{75}{20}) = 12 - 5\frac{19}{20} = 6\frac{1}{20}[/tex]
