[tex]\frac{\frac{1}{5}+0,2^2 }{3^2+(-1)^6}=\frac{\frac{1}{5}+(\frac{1}{5} )^2 }{3^2+1}=\frac{\frac{5}{25}+\frac{1}{25} }{9+1}=\frac{\frac{6}{25} }{10}=\frac{6}{25}\cdot\frac{1}{10}= \frac{3}{25} \cdot \frac{1}{5}=\frac{3}{125}[/tex]
