Odpowiedź:
[tex]a)\ \ \dfrac{2a-b^2}{4}=\dfrac{2*5-(-3)^2}{4}=\dfrac{10-9}{4}=\dfrac{1}{4}\\\\\\b)\ \ 3,5x+5y=3,5*(-5)+5*2=-17,5+10=-7,5\\\\\\c)\ \ 3x-\frac{1}{2}y=3*6-\frac{1}{\not2_{1} }*(-\not4^2)=18+2=20\\\\\\d)\ \ \dfrac{4}{t+3s}=\dfrac{4}{-3+3*(-2)}=\dfrac{4}{-3-6}=\dfrac{4}{-9}=-\dfrac{4}{9}\\\\\\e)\ \ 3mn+m^2n=3*2*(-6)+2^2*(-6)=-36+4*(-6)=-36-24=-60\\\\\\f)\ \ 2r(p+1)^2=2*(-2)*(-4+1)^2=-4*(-3)^2=-4*9=-36[/tex]
[tex]g)\ \ \frac{2}{7}(c-2d)^2=\frac{2}{7}(2-2*(-6))^2=\frac{2}{7}(2+12)^2=\frac{2}{7}*14^2=\frac{2}{\not7_{1}}*\not196^{28}=2*28=56\\\\\\h)\ \ 0,2d^2(c-d)=0,2*(-5)^2*(0-(-5))=0,2*25*(0+5)=5*5=25[/tex]
