Odpowiedź:
[tex]Zad.5\\\\a)\ \ 8\sqrt{3}+\sqrt{27}=8\sqrt{3}+\sqrt{9*3}=8\sqrt{3}+3\sqrt{3}=11\sqrt{3}\\\\\\b)\ \ 7\sqrt{5}-\sqrt{125}=7\sqrt{5}-\sqrt{25*5}=7\sqrt{5}-5\sqrt{5}=2\sqrt{5}\\\\\\c)\ \ \sqrt{48}+\sqrt{12}=\sqrt{16*3}+\sqrt{4*3}=4\sqrt{3}+2\sqrt{3}=6\sqrt{3}\\\\\\d)\ \ \sqrt{75}-\sqrt{300}=\sqrt{25*3}-\sqrt{100*3}=5\sqrt{3}-10\sqrt{3}=-5\sqrt{3}\\\\\\e)\ \ \sqrt{72}+\sqrt{50}-\sqrt{32}=\sqrt{36*2}+\sqrt{25*2}-\sqrt{16*2}=6\sqrt{2}+5\sqrt{2}-4\sqrt{2}=7\sqrt{2}[/tex]
[tex]f)\ \ \sqrt{20}+\sqrt{45}-\sqrt{500}=\sqrt{4*5}+\sqrt{9*5}-\sqrt{100*5}=2\sqrt{5}+3\sqrt{5}-10\sqrt{5}=-5\sqrt{5}[/tex]
