[tex]3)\\\\\frac{\sqrt[3]{4}*\sqrt[3]{-16}}{-8}=\frac{\sqrt[3]{4*(-16)} }{-8}=\frac{\sqrt[3]{-64} }{-8}=\frac{-4}{-8}=\frac{1}{2}=2^{{-1}}\\\\odp.\ C \\\\4)\\\\2\sqrt{2}*( \frac{1}{8})^{-\frac{4}{3}}=2*2^{\frac{1}{2}}*( 8^{-1} )^{-\frac{4}{3}}=2*2^{\frac{1}{2}}*( (2^3)^{-1} )^{-\frac{4}{3}}=2*2^{\frac{1}{2}}* 2^4=2^{1+\frac{1}{2}+4}=\\\\=2^{5\frac{1}{2}}=2^{\frac{11}{2}}\\\\liczba\ odwrotna\ do\ liczby : \\\\2^{\frac{11}{2}}=(2^{\frac{11}{2}})^{-1} =2^{-\frac{11}{2}}\\\\odp.\ \ \ C[/tex]
[tex]5)\\\\ \sqrt[3]{4^{-1}}*2^{\frac{1}{4}}*16^{\frac{1}{3}}= (4^{-1})^{\frac{1}{3}}*2^{\frac{1}{4}}* (2^4)^{\frac{1}{3}}= (2^2)^{-\frac{1}{3}}*2^{\frac{1}{4}}* 2^{\frac{4}{3}}= 2^{-\frac{2}{3}}*2^{\frac{1}{4}}* 2^{\frac{4}{3}} =\\\\=2^{-\frac{2}{3}+\frac{1}{4}+\frac{4}{3}}=2^{ \frac{2}{3}+\frac{1}{4}}= 2^{ \frac{8}{12}+\frac{3}{12}}=2^{\frac{11}{12}}[/tex]
