[tex]dane:\\v_1 = 2\frac{m}{s}\\t = 8 \ s\\v_2 = 22\frac{m}{s}\\m = 200 \ kg\\szukane:\\F = ?\\\\Rozwiazanie\\\\F = m\cdot a\\\\ale:\\a = \frac{\Delta v}{t } = \frac{(22-2)\frac{m}{s}}{8 \ s} = \frac{20\frac{m}{s}}{8 \ s} = 2,5\frac{m}{s^{2}}\\\\F = 200 \ kg\cdot2,5\frac{m}{s^{2}}=500 \ N[/tex]
Odp. Szukana siła F = 500 N.
