5.
[tex]dane:\\F_{g} = 368 \ N\\g = 10\frac{N}{kg}\\szukane:\\m = ?\\\\Rozwiazanie\\\\F_{g} = m\cdot g \ \ /:g\\\\m = \frac{F_{g}}{g}\\\\m = \frac{368 \ N}{10\frac{N}{kg}}\\\\m = 36,8 \ kg[/tex]
6.
[tex]dane:\\d = 2,5\frac{g}{cm^{3}}\\V = 65 \ cm^{3}}\\szukane:\\m = ?\\\\Rozwiazanie\\\\d = \frac{m}{V} \ \ |\cdot V\\\\m = V\cdot d\\\\m = 65 \ cm^{3}\cdot2,5\frac{g}{cm^{3}}\\\\m = 162,5 \ g[/tex]
