Odpowiedź:
[tex]a) 1\frac{5}{6}:3\frac{2}{3}*1\frac{1}{7}=\frac{11}{6}:\frac{11}{3}*\frac{8}{7}=\frac{11}{6}*\frac{3}{11}*\frac{8}{7}=\frac{3}{6}*\frac{8}{7}=\frac{24}{42}=\frac{12}{21}\\\\b)(\frac{1}{2})^3*2\frac{2}{3}:1\frac{1}{6}=\frac{1}{8}*\frac{8}{3}:\frac{7}{6}=\frac{1}{3}*\frac{6}{7}=\frac{6}{21}\\\\c)1\frac{1}{4}*6-3:1\frac{1}{5}=\frac{5}{4}*\frac{6}{1}-\frac{3}{1}*\frac{5}{6}=\frac{15}{2}-\frac{5}{2}=\frac{10}{2}=5\\[/tex][tex]d)(4\frac{3}{8}-1\frac{2}{3}):3\frac{3}{4}=(\frac{35}{8}-\frac{5}{3})*\frac{4}{15}=(\frac{105}{24}-\frac{40}{24})*\frac{4}{15}=\frac{65}{24}*\frac{4}{15}=\frac{65}{90}=\frac{13}{18}\\\\e)2\frac{1}{5}-1\frac{1}{6}:2\frac{1}{3}=\frac{11}{5}-\frac{7}{6}*\frac{3}{7}=\frac{11}{5}-\frac{1}{2}=\frac{22}{10}-\frac{5}{10}=\frac{17}{10}=1\frac{7}{10}\\\\[/tex][tex]\\f)[(\frac{3}{8}+\frac{1}{6}):3\frac{1}{4}]-(\frac{1}{3})^3=[(\frac{9}{24}+\frac{4}{24})*\frac{4}{13}]-\frac{1}{27}=(\frac{13}{24}*\frac{4}{13})-\frac{1}{27}=\frac{4}{24}-\frac{1}{27}=\frac{1}{6}-\frac{1}{27}=\frac{9}{54}-\frac{2}{54}=\frac{7}{54}\\\\[/tex][tex]g)\frac{5}{8}:1\frac{2}{3}+1\frac{4}{5}*\frac{5}{6}-\frac{5}{9}*(1\frac{3}{4}-\frac{2}{5})+1\frac{5}{6}=\frac{5}{8}*\frac{3}{5}+\frac{9}{5}*\frac{5}{6}-\frac{5}{9}*(\frac{35}{20}-\frac{8}{20})+\frac{11}{6}=\frac{3}{8}+\frac{3}{2}-\frac{5}{9}*\frac{27}{20}+\frac{11}{6}=\frac{3}{8}+\frac{12}{8}-\frac{6}{8}+\frac{11}{6}=\frac{27}{24}+\frac{44}{24}=\frac{71}{24}=2\frac{23}{24}[/tex][tex]h)1\frac{1}{3}*1\frac{1}{4}-1\frac{1}{2}:1\frac{1}{5}+1\frac{1}{8}:(1\frac{1}{8}-\frac{3}{4})+1\frac{5}{6}=\frac{4}{3}*\frac{5}{4}-\frac{3}{2}*\frac{5}{6}+\frac{9}{8}*\frac{8}{3}+\frac{11}{6}=\frac{5}{3}-\frac{5}{6}+\frac{9}{3}+\frac{11}{6}=\frac{10}{6}-\frac{5}{6}+\frac{18}{6}+\frac{11}{6}=\frac{5}{6}+\frac{18}{6}+\frac{11}{6}=\frac{34}{6}=5\frac{2}{3}[/tex]
