Hej!
[tex] \sqrt{12} - 2 \sqrt{18} + 3 \sqrt{48} = \\ \\ = \sqrt{4 \times 3} - 2 \sqrt{9 \times 2} + 3 \sqrt{16 \times 3} = \\ \\ = 2 \sqrt{3} - 2 \times 3 \sqrt{2} + 3 \times 4 \sqrt{3} = 2 \sqrt{3} - 6 \sqrt{2} + 12 \sqrt{3} = \\ \\ = 14 \sqrt{3} - 6 \sqrt{2} [/tex]
Pozdrawiam! - Julka
