Odpowiedź:
1. a²+b²=c²
[tex] {2}^{2} + {x}^{2} = 5\sqrt{5} \\ 4 + {x}^{2} = 125 \\ {x}^{2} = 121 \\ x = 11[/tex]
2.
[tex] {3}^{2} + 3 \sqrt{8} = {x}^{2} \\ 9 + 72 = {x}^{2} \\ {x}^{2} = 81 \\ x = 9[/tex]
3. 8²+x²=17²
64+x²=289
x²=225
x=15
4. 2²+x²= 10 pierwiastków z 2
4+x²= 200
x²=196
x=14
