Odpowiedź:
x³ + 7x² + 6x = 0
x(x² + 7x + 6) = 0
x = 0 ∨ x² + 7x + 6 = 0
x² + 7x + 6 = 0
a = 1 , b = 7 , c = 6
Δ = b² - 4ac = 7² - 4 * 1 * 6 = 49 - 24 = 25
√Δ = √25 = 5
x₁ = (- b - √Δ)/2a = (- 7 - 5)/2 = - 12/2 = - 6
x₂ = (- b + √Δ)/2a = (- 7 + 5)/2 = - 2/2 = - 1
x = 0 ∨ x = - 6 ∨ x = - 1
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