Odpowiedź:
[tex] \frac{ \sqrt{3} \times \sqrt{27} }{ \sqrt{72} \div \sqrt{8} } = \frac{ \sqrt{81} }{ \sqrt{9} } = \frac{9}{3} = 3[/tex]
[tex] \frac{ { \sqrt{125} }^{2} }{ \sqrt[3]{125} } = \frac{125}{5} = 25[/tex]
[tex]( \sqrt[3]{192} \div \sqrt[3]{6} ) \times \sqrt[3]{2} = \sqrt[3]{32} \times \sqrt[3]{2} = \sqrt[3]{64} = 4[/tex]
[tex]12 \sqrt{1 \frac{25}{144} } = 12 \times \sqrt{ \frac{169}{144} } = 12 \times \frac{13}{12} = 13[/tex]
