Odpowiedź:
a) III
1 [tex]\frac{1}{3} : 1\frac{5}{6} = \frac{4}{3} * \frac{6}{11} = \frac{24}{33} = \frac{8}{11}[/tex]
b) I
[tex]1\frac{1}{3} + 2\frac{3}{4} = 1\frac{4}{12} + 2\frac{9}{12} = 3\frac{13}{12} = 4\frac{1}{12}[/tex]
c) IV
[tex]1\frac{5}{8} * 1\frac{1}{3} = \frac{13}{8} * \frac{4}{3} = \frac{52}{24} = 2\frac{4}{24} = 2\frac{1}{6}[/tex]
d) II
[tex]2\frac{1}{9} - 1\frac{1}{6} = 1\frac{20}{18} - 1\frac{3}{18} = \frac{17}{18}[/tex]
Szczegółowe wyjaśnienie:
