Odpowiedź:
[tex]\frac{2}{3}*(7\frac{4}{20}-3\frac{3}{4})=\frac{2}{3}*(7\frac{4}{20}-3\frac{15}{20})=\frac{2}{3}*(6\frac{24}{20}-3\frac{15}{20})=\frac{2}{3}*3\frac{9}{20}=\frac{\not2^1}{\not3_{1}}*\frac{\not69^2^3}{\not20_{10}}=\frac{23}{10}=2\frac{3}{10}[/tex]
[tex]7\frac{4}{5}-1\frac{1}{5}*2\frac{1}{2}=7\frac{4}{5}-\frac{\not6^3}{\not5_{1}}*\frac{\not5^1}{\not2_{1}}=7\frac{4}{5}-3=4\frac{4}{5}[/tex]
