[tex]\sqrt[3]{8\cdot27} = \sqrt[3]{8}\cdot\sqrt[3]{27} = \sqrt[3]{2^{3}}\cdot\sqrt[3]{3^{3}} = 2\cdot3 = 6 \ - \ K\\\\\sqrt[3]{27+27+8+1+1}=\sqrt[3]{64} = \sqrt[3]{4^{3}} = 4 \ - \ O\\\\\sqrt[3]{100}\cdot\sqrt[3]{10} + \sqrt[3]{-1} = \sqrt[3]{100\cdot10}-\sqrt[3]{1} = \sqrt[3]{1000}-1 10-1 = 9 \ - \ N\\\\\sqrt[3]{2}\cdot\sqrt[3]{2}\cdot\sqrt[3]{2} = \sqrt[3]{2\cdot2\cdot2} = \sqrt[3]{2^{3}} = 2 \ - \ F\\\\\sqrt[3]{10^{3}}\cdot\sqrt[3]{8} = 10\cdot2 = 20 \ - \ A[/tex]
[tex]2+2\sqrt[3]{27} = 2+2\sqrt[3]{3^{3}} = 2+2\cdot3 = 2 + 6 = 8 \ - \ B\\\\\sqrt[3]{27000}+\sqrt[3]{-8} = \sqrt[3]{30^{3}}-\sqrt[3]{2^{3}} = 30-2 = 28 \ - \ U\\\\\sqrt{25}+3\sqrt{4} = 5+3\cdot2 = 5+6 = 11 \ - \ L\\\\\sqrt{7}\cdot\sqrt{7} = \sqrt{7\cdot7} = \sqrt{49} = 7 \ - \ A\\\\\sqrt{36\cdot64} = \sqrt{36}\cdot\sqrt{64} = 6\cdot8 = 48 \ - \ C\\\\\sqrt{36+64} = \sqrt{100} = 10 \ - \ J\\\\\sqrt[3]{19\cdot19\cdot19}-\sqrt[3]{-1} = \sqrt[3]{19^{3}}-(-1) = 19+1 = 20 \ - \ A[/tex]
Hasło: KONFABULACJA
Znaczenie hasła: nieświadome zmyślanie, koloryzowanie.
Znaczenie słowa "muflon": dzika korsykańska koza
