[tex](4^{2} :\frac{4^{2} }{2^{3} }) + (\sqrt{81} * 2^{3} ) - \frac{\sqrt{162}}{4^{2} + \sqrt{16} } :\frac{4}{18} = ( 4^{2} * \frac{2^{3} }{4^{2} } ) + (9*8) -\frac{9\sqrt{2} }{16+4} * \frac{18}{4} = 2^{3}+ 72 -\frac{9\sqrt{2} }{20} *\frac{9}{2} = 8+72-\frac{9\sqrt{2} }{20} *\frac{9}{2} =80 - \frac{81\sqrt{2} }{40}[/tex]
Mam nadzieję że pomogłam ((: