Odpowiedź:
zad 3
[(- 4)² + (- 2)³ ] * (√121 - √169) = (16 - 8) * (11 - 13) = 8 * (- 2) = - 16
zad 4
[√(1 9/16) : (- 1 1/4)² - 2²] * (2 1/2)³ = [√(25/16) : (- 5/4)² - 4] * (5/4)³ =
= (5/4 : 25/16 - 4) * 125/64 = (5/4 * 16/25 - 4) * 125/64 =
= (4/5 - 4) * 125/64 = - 3 1/5 * 125/64 = - 16/5 * 125/64 = - 25/4 = - 6 1/4