Odpowiedź:
[tex]2a - 3b + 4 {c}^{2} - 7a + 12b - 3 \frac{1}{2} {c}^{2} = - 5a + 9b + \frac{1}{2} {c}^{2} = - 5 \times ( - 3) + 9 \times ( - \frac{1}{6} ) + \frac{1}{2} \times {2}^{2} = 15 - 1 \frac{1}{2} + 2 = 15 \frac{1}{2} [/tex]
[tex] - 3abc + 2 {a}^{2} {b}^{2} - 3ab - {a}^{2} {b}^{2} + 4abc = abc + {a}^{2} {b}^{2} - 3ab = ( - 3) \times ( - \frac{1}{6} ) \times 2 + {( - 3)}^{2} \times {( - \frac{1}{6}) }^{2} - 3 \times ( - 3) \times ( - \frac{1}{6} ) = 1 + 9 \times \frac{1}{36} -( - 9) \times ( - \frac{1}{6} ) = 1 + \frac{1}{4} - 1 \frac{1}{2} = 1 + \frac{1}{4} - 1 \frac{2}{4} = - \frac{1}{4} [/tex]
[tex]7ac - 4ab + 8bc - 6ac + 12ab - 10bc = ac + 8ab - 2bc = ( - 3) \times 2 + 8 \times ( - 3) \times ( - \frac{1}{6} ) - 2 \times ( - \frac{1}{6} ) \times 2 = - 6 + 4 - \frac{2}{3} = - 2 \frac{2}{3} [/tex]
