Odpowiedź:
[tex]b)\ \ (8\frac{1}{2}-4,75):15=(8,5-4,75):15=3,75:15=0,25\\\\\\d)\ \ [(13-11\frac{1}{2}):0,03]*0,026=[(12\frac{2}{2}-11\frac{1}{2}):0,03]*0,026=(1\frac{1}{2}:0,03)*\frac{26}{1000}=\\\\=(1,5:0,03)*\frac{13}{500}=\not50^1*\frac{13}{\not500_{10}}=\frac{13}{10}=1\frac{3}{10}=1,3[/tex]
[tex]f)\ \ \frac{1}{3}:0,6+625:100-4\frac{1}{3}-\frac{1}{3}*(3,6-1\frac{2}{3})+2\frac{3}{4}=\\\\=\frac{1}{3}:\frac{3}{5}+6,25-4\frac{1}{3}-\frac{1}{3}*(3\frac{3}{5}-1\frac{2}{3})+2\frac{3}{4}=\frac{1}{3}*\frac{5}{3}+6,25-4\frac{1}{3}-\frac{1}{3}*(3\frac{9}{15}-1\frac{10}{15})+2\frac{3}{4}=\\\\=\frac{5}{9}+6\frac{1}{4}-4\frac{1}{3}-\frac{1}{3}*(2\frac{24}{15}-1\frac{10}{15})+2\frac{3}{4}=\frac{5}{9}+8\frac{4}{4}-4\frac{1}{3}-\frac{1}{3}*1\frac{14}{15}=[/tex]
[tex]=\frac{5}{9}+9-4\frac{1}{3}-\frac{1}{3}*\frac{29}{15}=9\frac{5}{9}-4\frac{1}{3}-\frac{29}{45}=9\frac{25}{45}-4\frac{15}{45}-\frac{29}{45}=5\frac{10}{45}-\frac{29}{45}=4\frac{55}{45}-\frac{29}{45}=4\frac{26}{45}[/tex]
[tex]g)\ \ 1\frac{1}{3}:1,6-1,05:1,5+3,5*(3,8-2\frac{3}{5})+0,75=\\\\=\frac{4}{3}:\frac{16}{10}-0,7+3,5*(3,8-2,6)+0,75=\frac{4}{3}:\frac{8}{5}-0,7+3,5*1,2+0,75=\\\\=\frac{\not4^1}{3}*\frac{5}{\not8_{2}}-0,7+4,2+0,75=\frac{5}{6}+4,25=\frac{5}{6}+4\frac{1}{4}=\frac{10}{12}+4\frac{3}{12}=4\frac{13}{12}=5\frac{1}{12}[/tex]
