Odpowiedź:
[tex]2^6*(\frac{1}{2})^6=(2*\frac{1}{2})^6=1^6=1\\\\\\(2\frac{1}{2})^5:(2\frac{1}{2})^7=(2\frac{1}{2})^{5-7}=(\frac{5}{2})^{-2}=(\frac{2}{5})^2=\frac{4}{25}\\\\\\\dfrac{2^5*2*2}{(2^3)^2}=\dfrac{2^{5+1+1}}{2^6}=\dfrac{2^7}{2^6}=2^{7-6}=2^1=2[/tex]
