Odpowiedź:
[tex]\left \{{{3x-2y=10/*-2}}\atop {2x+3y=-2/*3}}\right.[/tex]
[tex]\left \{ {{-6x+4y=-20}\atop {6x+9y=-6}}\right.[/tex]
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13y=-26/:13
y=-2
3x-2*(-2)=10
3x+4=10
3x=10-4
3x=6/:3
x=2
(x,y)=(2 , -2)
Szczegółowe wyjaśnienie:
sprawdzenie
[tex]\left \{ {{3*2-2*(-2)=10} \atop {2*2+3*(-2)=-2}} \right.[/tex]
[tex]\left\{ {{6+4=10}\atop {4-6=-2}}\right.[/tex]
[tex]\left\{{{10=10} \atop {-2=-2}}\right.[/tex]
