Odpowiedź :
Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]2\sqrt{3}=\sqrt{4}[/tex] *[tex]\sqrt{3}[/tex]=[tex]\sqrt{4*3} = \sqrt{12}[/tex]
[tex](2\sqrt{2})^{2} = 2^{2} * \sqrt{2}^{2}= 4*2=8[/tex]
[tex]\sqrt{6} * \sqrt{3} =\sqrt{6*3} = \sqrt{18}[/tex]
[tex]3\sqrt{2} = \sqrt{9} *\sqrt{2} = \sqrt{9*2} =\sqrt{18}[/tex]
[tex]\sqrt{32} *\sqrt{2} = \sqrt{32*2} = \sqrt{64} = 8[/tex]
Pary liczb równych to:
[tex]2\sqrt{3}[/tex] i [tex]\sqrt{12}[/tex]
[tex](2\sqrt{2} )^{2}[/tex] i [tex]\sqrt{32} * \sqrt{2}[/tex]
[tex]\sqrt{6} * \sqrt{3}[/tex] i [tex]3\sqrt{2}[/tex]
2 [tex]\sqrt{3}[/tex] i [tex]\sqrt{12}[/tex]
[tex]\sqrt{6}[/tex] * [tex]\sqrt{3}[/tex] i 3[tex]\sqrt{2}[/tex]
( 2 [tex]\sqrt{2}[/tex] ) [tex]^{2}[/tex] i [tex]\sqrt{32}[/tex] * [tex]\sqrt{2}[/tex]
Proszę o naj