Odpowiedź:
a) [tex]sin\alpha =\frac{3}{5}[/tex]
[tex]cos\alpha =\frac{4}{5}[/tex]
[tex]tg\alpha =\frac{3}{4}[/tex]
b)
[tex]5^{2} +12^{2} =c^{2} \\25+144=c^{2} \\169=c^{2} \\c=13[/tex]
[tex]sin\alpha =\frac{5}{13}[/tex]
[tex]cos\alpha =\frac{12}{13}[/tex]
[tex]tg\alpha =\frac{5}{12}[/tex]
c)
[tex]\sqrt{3} ^{2} +b^{2} =(2\sqrt{3} )^{2} \\3+b^{2} =12\\b^{2} =12-3=9\\b=3[/tex]
[tex]sin\alpha =\frac{3}{2\sqrt{3} } =\frac{3\sqrt{3} }{6} =\frac{\sqrt{3} }{2}[/tex]
[tex]cos\alpha =\frac{\sqrt{3} }{2\sqrt{3} } =\frac{1}{2}[/tex]
[tex]tg\alpha =\frac{3}{\sqrt{3} } =\frac{3\sqrt{3} }{3} =\sqrt{3}[/tex]
[tex]sin\beta =\frac{\sqrt{3} }{2\sqrt{3} } =\frac{1}{2}[/tex]
[tex]cos\beta =\frac{3}{2\sqrt{3} }= \frac{\sqrt{3} }{2}[/tex]
[tex]tg\beta =\frac{\sqrt{3} }{3}[/tex]
