[tex]1a)\\\\\sqrt[3]{4}*\sqrt[3]{250}-\sqrt {7}*\sqrt {63}= \sqrt[3]{4*250}- \sqrt {7*63}= \sqrt[3]{1000}- \sqrt {441}=10-21=-11\\\\b)\\\\\sqrt[3]{3\frac{3}{8}}=\sqrt[3]{ \frac{27}{8}}= \sqrt[3]{( \frac{3}{2})^3}=\frac{3}{2}=1\frac{1}{2}\\\\c)\\\\\sqrt{\frac{25}{36}}=\sqrt{(\frac{5}{6})^2}=\frac{5}{6}\\\\d)\\\\(\sqrt[5]{6})^{10}=( (6)^{\frac{1}{5}} )^{10}=6^{\frac{1}{5}*10}=6^{2}=36[/tex]
[tex]2a)\\\\ \frac{7}{\sqrt{5}}=\frac{7}{\sqrt{5}}*\frac{ \sqrt{5}}{\sqrt{5}}=\frac{7\sqrt{5}}{5}\\\\b)\\\\\frac{6}{2\sqrt[3]{5}}=\frac{6}{2\sqrt[3]{5}}*\frac{\sqrt[3]{25} }{ \sqrt[3]{25}}=\frac{6\sqrt[3]{25}}{2*\sqrt[3]{5*25}}=\frac{6\sqrt[3]{25}}{2*\sqrt[3]{125}}=\frac{6\sqrt[3]{25}}{2*5}=\frac{3\sqrt[3]{25}}{ 5} \\\\c)\\\\\frac{4\sqrt{3}}{7-2\sqrt{3}}=\frac{4\sqrt{3}}{7-2\sqrt{3}} *\frac{7+2\sqrt{3}}{7+2\sqrt{3}}=\frac{28\sqrt{3}+24}{49-12}= \frac{28\sqrt{3}+24}{37}[/tex]
[tex]3a)\\\\ 0,25\sqrt{32}-\frac{1}{3}\sqrt{72}= \frac{25}{100}\sqrt{16*2}-\frac{1}{3}\sqrt{36*2}=\frac{1}{4}*4\sqrt{2}-\frac{1}{3}*6\sqrt{2}=\sqrt{2}-2\sqrt{2}=-\sqrt{2}\\\\b)\\\\5\sqrt[3]{81}-2\sqrt[3]{3}=5\sqrt[3]{27*3}-2\sqrt[3]{3}=5*3\sqrt[3]{3}-2\sqrt[3]{3}=15\sqrt[3]{3}-2\sqrt[3]{3}=13\sqrt[3]{3}[/tex]
