Odpowiedź:
zad 1
[tex]\left \{ {{\frac{1}{2}x-3y=2} \atop {-4x-y=9/*(-3)}} \right.[/tex]
[tex]\left \{ {{\frac{1}{2}x-3y=2} \atop {12x+3y=-27}} \right.[/tex]
---------------------
12,5x=-25/:12,5
x=-2
-4*(-2)-y=9
8-y=9
-y=9-8
-y=1
y=-1
(x,y)=(-2,-1)
ODP.C
zad 2
ODP C
[tex]\left \{ {{\frac{2}{3}x-2y=2/*3} \atop {x-3y=4/*(-2)}} \right.[/tex]
[tex]\left \{ {{2x-6y=6} \atop {-2x+6y=-8}} \right.[/tex]
--------------------
0≠14
(x,y)∉∅
Szczegółowe wyjaśnienie:
