Odpowiedź :
[tex]V=\dfrac{s}{t}\\\\t=\dfrac{s}{V}[/tex]
[tex]P=\dfrac{1}{2}(a+b)h\\\\2P=(a+b)h\\\\h=\dfrac{2P}{a+b}[/tex]
[tex]v = \frac{s}{t} \ \ |\cdot t\\\\v\cdot t = s \ \ /:v\\\\t = \frac{s}{v}\\---------[/tex]
[tex]P = \frac{1}{2}(a+b)h \ \ |\cdot 2\\\\(a+b)h = 2P \ \ /:(a+b)\\\\h = \frac{2P}{a+b}[/tex]