Odpowiedź :
[tex]dla \ \ x = \sqrt{2}\\\\4x^{2}-26x-65 = 4\cdot(\sqrt{2})^{2}-26\cdot\sqrt{2}-65 = 4\cdot2 - 26\sqrt{2}-65 = 8-26\sqrt{2}-65 =\\\\= -57-26\sqrt{2}[/tex]
[tex]dla \ \ x = \sqrt{2}\\\\4x^{2}-26x-65 = 4\cdot(\sqrt{2})^{2}-26\cdot\sqrt{2}-65 = 4\cdot2 - 26\sqrt{2}-65 = 8-26\sqrt{2}-65 =\\\\= -57-26\sqrt{2}[/tex]