Odpowiedź :
[tex]a) \ \sqrt{81} - \sqrt[3]{-27} = 9 - (-3) = 9+3 = 12\\\\b) \ 2\sqrt{\frac{1}{36}}+\frac{\sqrt{144}}{4} =2\cdot\frac{1}{6} + \frac{12}{4} = \frac{1}{3}+3 = 3\frac{1}{3}[/tex]
[tex]a) \ \sqrt{81} - \sqrt[3]{-27} = 9 - (-3) = 9+3 = 12\\\\b) \ 2\sqrt{\frac{1}{36}}+\frac{\sqrt{144}}{4} =2\cdot\frac{1}{6} + \frac{12}{4} = \frac{1}{3}+3 = 3\frac{1}{3}[/tex]