[tex]dane:\\v_{o} = 72\frac{km}{h} = 72\cdot\frac{1000 \ m}{3600 \ s} = 20\frac{m}{s}\\t = 4 \ s\\v = 0\\szukane:\\s = ?\\\\Rozwiazanie\\\\s = v_{o}t - \frac{1}{2}at^{2}\\\\a = \frac{v_{o}}{t} = \frac{20\frac{m}{s}}{4 \ s} = 5\frac{m}{s^{2}}\\\\s = 20\frac{m}{s}\cdot 4 \ s - \frac{1}{2}\cdot5\frac{m}{s^{2}}\cdot(4 \ s)^{2} \\\\s = 80 \ m - 40 \ m = 40 \ m[/tex]
Odp. Droga hamowania tego samochodu s = 40 m.
